regex for xquery

On 08/10/2014 13:37, Rob Stapper wrote: > > Hi, > > Basically I want to break down the path-expression of a node in my XML > into its elementary steps. > > QName: > “Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]” > must become QName-sequence: > (“Q{http://www.w3.org/2005/xpath-functions}root()”, ”Q{}A[1] ”, > ”Q{}B[1] ”, ”Q{}C[1] ”, ”Q{}D[1]”) > > So I need to break the path-expression down on the “/”-characters > which aren’t part of the namespace-uries. > > I’m using the “fn:tokenize”-function for this. The function uses a > “regular expression” for it’s separator. > > Unfortunately my regex-experience is zero (well, two days by now). I > came up with the next brilliant ;-) solution: fn:tokenize( path( > $node), “/(?=Q)”). > > Again, unfortunately, this doesn’t work because the xquery-flavor of > regex doesn’t support looking around. > > Sure, I can use “/Q” as pattern and subsequently stick a “Q” in front > of every substring (except the first one) but I’m looking for a solid > solution. > > I there anyone out there with enough “regex-for-xquery”- experience to > help me with this? > > Big thanx for that in advance. > > @Christian: On the other hand I can imagine that within Basex the > path-expression is built from these elementary steps. > > If so, is it in any way possibly to retrieve this elementary steps > sequence instead of this path-expression? > > Thanx, > > Rob Stapper > > > > ------------------------------------------------------------------------ > <http://www.avast.com/> > > Dit e-mailbericht bevat geen virussen en malware omdat avast! > Antivirus <http://www.avast.com/> actief is. > >

> @Christian: On the other hand I can imagine that within Basex the

> If so, is it in any way possibly to retrieve this elementary steps

On Wed, Oct 8, 2014 at 2:10 PM, Marco Lettere <marco.lettere at dedalus.eu> wrote: > Hi Rob, > don't know whether your prefix is constant. > > If it is then > > let $prefix := "Q{http://www.w3.org/2005/xpath-functions}root()" > let $inpstr := "Q{http://www.w3.org/2005/xpath-functions > }root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]" > return ($prefix, > tokenize(substring-after($inpstr, $prefix),"/")) > > should do the job. > M. > > > On 08/10/2014 13:37, Rob Stapper wrote: > > Hi, > > > > Basically I want to break down the path-expression of a node in my XML > into its elementary steps. > > QName: “Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]” > must become QName-sequence: (“Q{http://www.w3.org/2005/xpath-functions}root()”, > ”Q{}A[1] ”, ”Q{}B[1] ”, ”Q{}C[1] ”, ”Q{}D[1]”) > > > > So I need to break the path-expression down on the “/”-characters which > aren’t part of the namespace-uries. > > > > I’m using the “fn:tokenize”-function for this. The function uses a > “regular expression” for it’s separator. > > Unfortunately my regex-experience is zero (well, two days by now). I came > up with the next brilliant ;-) solution: fn:tokenize( path( $node), > “/(?=Q)”). > > Again, unfortunately, this doesn’t work because the xquery-flavor of regex > doesn’t support looking around. > > Sure, I can use “/Q” as pattern and subsequently stick a “Q” in front of > every substring (except the first one) but I’m looking for a solid > solution. > > > > I there anyone out there with enough “regex-for-xquery”- experience to > help me with this? > > Big thanx for that in advance. > > > > @Christian: On the other hand I can imagine that within Basex the > path-expression is built from these elementary steps. > > If so, is it in any way possibly to retrieve this elementary steps > sequence instead of this path-expression? > > > > Thanx, > > > > Rob Stapper > > > ------------------------------ > <http://www.avast.com/> > > Dit e-mailbericht bevat geen virussen en malware omdat avast! Antivirus > <http://www.avast.com/> actief is. > > >

Van: basex-talk-bounces at mailman.uni-konstanz.de [mailto:basex-talk-bounces at mailman.uni-konstanz.de] Namens Christian Grün Verzonden: woensdag 8 oktober 2014 14:18 Aan: Marco Lettere CC: BaseX Onderwerp: Re: [basex-talk] regex for xquery Hi Rob, here's yet another solution: let $path := "Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1] <http://www.w3.org/2005/xpath-functions%7droot()/Q%7b%7dA%5b1%5d/Q%7b%7dB%5b1%5d/Q%7b%7dC%5b1%5d/Q%7b%7dD%5b1%5d> " return analyze-string($path, '(Q\{.*?\}.*?)(/|$)')/fn:match/fn:group[1]/string() > @Christian: On the other hand I can imagine that within Basex the path-expression is built from these elementary steps. > If so, is it in any way possibly to retrieve this elementary steps sequence instead of this path-expression? Currently, there is no other way to retrieve paths, so you'll have to manually split the path as indicated above.. Christian On Wed, Oct 8, 2014 at 2:10 PM, Marco Lettere <marco.lettere at dedalus.eu> wrote: Hi Rob, don't know whether your prefix is constant. If it is then let $prefix := "Q{http://www.w3.org/2005/xpath-functions}root()" let $inpstr := "Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]" return ($prefix, tokenize(substring-after($inpstr, $prefix),"/")) should do the job. M. On 08/10/2014 13:37, Rob Stapper wrote: Hi, Basically I want to break down the path-expression of a node in my XML into its elementary steps. QName: “Q{http://www.w3.org/2005/xpath-functions}root()/Q{}A[1]/Q{}B[1]/Q{}C[1]/Q{}D[1]” must become QName-sequence: (“Q{http://www.w3.org/2005/xpath-functions}root()”, ”Q{}A[1] ”, ”Q{}B[1] ”, ”Q{}C[1] ”, ”Q{}D[1]”) So I need to break the path-expression down on the “/”-characters which aren’t part of the namespace-uries. I’m using the “fn:tokenize”-function for this. The function uses a “regular expression” for it’s separator. Unfortunately my regex-experience is zero (well, two days by now). I came up with the next brilliant ;-) solution: fn:tokenize( path( $node), “/(?=Q)”). Again, unfortunately, this doesn’t work because the xquery-flavor of regex doesn’t support looking around. Sure, I can use “/Q” as pattern and subsequently stick a “Q” in front of every substring (except the first one) but I’m looking for a solid solution. I there anyone out there with enough “regex-for-xquery”- experience to help me with this? Big thanx for that in advance. @Christian: On the other hand I can imagine that within Basex the path-expression is built from these elementary steps. If so, is it in any way possibly to retrieve this elementary steps sequence instead of this path-expression? Thanx, Rob Stapper _____ <http://www.avast.com/> Dit e-mailbericht bevat geen virussen en malware omdat avast! Antivirus <http://www.avast.com/> actief is. --- Dit e-mailbericht bevat geen virussen en malware omdat avast! Antivirus-bescherming actief is. http://www.avast.com